Answer
$I=5.97\times10^{-5}\frac{W}{m^2}$
Work Step by Step
We know that intensity $'I'$ of an isotropic sound can be determined from the following equation
$I=\frac{P}{4{\pi}{r^2}}$
putting the values, we get
$I=\frac{30}{4(3.14)(200)^2}$
$I=5.97\times10^{-5}\frac{W}{m^2}$
