Answer
The second lowest frequency is $$(n=1) f_{\min , 2}=[2(1)+1](343 \mathrm{Hz})=1029 \mathrm{Hz}=3 f_{\min , 1}$$
Thus, the factor is $3 .$
Work Step by Step
The second lowest frequency is $$(n=1) f_{\min , 2}=[2(1)+1](343 \mathrm{Hz})=1029 \mathrm{Hz}=3 f_{\min , 1}$$
Thus, the factor is $3 .$
