Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 17 - Waves-II - Problems - Page 507: 14f

Answer

$$3141.59\;rad/s$$

Work Step by Step

Here, time period of the wave is: $T=2\;ms$ Therefore, the angular frequency is: $\omega=\frac{2\pi}{T}$ Substituting the given values $\omega=\frac{2\pi}{2\times10^{-3}}\;rad/s$ or, $\boxed{\omega=3141.59\;rad/s}$
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