Answer
The picture is attached below.
Work Step by Step
Pent-1-yne, when reacted with two equivalents of $Br_{2}$, forms 1,1,2,2-tetrabromopentane.
The triple bond in pent-1-yne found between carbon number 1 and carbon number 2 breaks, and the bond between both the $Br-Br$ molecules also breaks. $Br$ atoms attach with these carbons and forms a single bond with this carbon. The triple bond is converted into a single bond, and the product formed is 1,1,2,2-tetrabromopentane.
