Answer
The picture is attached below.
Work Step by Step
Pent-1-yne, when reacted with one equivalent of $Br_{2}$, forms 1,2-dibromopent-1-ene.
The triple bond in pent-1-yne found between carbon number 1 and carbon number 2 breaks, and the bond between $Br−Br$ also breaks. $Br$ atoms attach with these carbons and form a single bond with this carbon. The triple bond is converted into a double bond. The product formed has E and Z isomers.
