Answer
The picture is attached below.
Work Step by Step
Pent-1-yne, when reacted with one equivalent of H-Cl, forms 2-chloropent-1-ene.
The triple bond in pent-1-yne found between carbon number 1 and carbon number 2 breaks, and the bond between $H-Cl$ also breaks. H and Cl atoms attach with these carbons and form a single bond with this carbon. Chlorine attaches to carbon number 2 whereas Hydrogen forms a bond with carbon number 1.