Chemistry: The Molecular Nature of Matter and Change 7th Edition

Published by McGraw-Hill Education
ISBN 10: 007351117X
ISBN 13: 978-0-07351-117-7

Chapter 19 - Problems: 19.18

Answer

pH of buffer = 10.07

Work Step by Step

(A) Given : 1. [conjugate base] = [H2BO3-] = 0.82 M 2. [acid] = [H3BO3] = 0.12 M 3. pKa of Boric Acid (H3BO3) = 9.24 2 (B) Formulae : 1. Henderson - Hasselbalch equation of a buffer : pH = pKa + log [conjugate base] / [acid] 3 (C) Solution : pH = pKa + log [conjugate base] / [acid] So, pH = 9.24 + log (0.82 / 0.12) = 9.24 + 0.83 = 10.07 Hence, pH of the buffer is 10.07. 4 (D) Answer : pH of buffer = 10.07
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