Answer
pH of buffer = 8.49
Work Step by Step
1
(A) Given :
1. [conjugate base] = [BrO-] = 0.68 M
2. [acid] = [HBrO] = 0.95 M
3. pKa of acid (HBrO) = 8.64
2
(B) Formulae :
1. Henderson - Hasselbalch equation of a buffer :
pH = pKa + log [conjugate base] / [acid]
3
(C) Solution :
pH = pKa + log [conjugate base] / [acid]
So,
pH = 8.64 + log (0.68 / 0.95)
= 8.64 - 0.15
= 8.49
Hence, pH of the buffer is 8.49.
4
(D) Answer :
pH of buffer = 8.49