Chemistry: The Molecular Nature of Matter and Change 7th Edition

Published by McGraw-Hill Education
ISBN 10: 007351117X
ISBN 13: 978-0-07351-117-7

Chapter 19 - Problems: 19.17

Answer

pH of buffer = 10.03

Work Step by Step

1 (A) Given : 1. [conjugate base] = [C6H5O-] = 1.3 M 2. [acid] = [C6H5OH] = 1.2 M 3. pKa of Phenol (C6H5OH) = 10.00 2 (B) Formulae : 1. Henderson - Hasselbalch equation of a buffer : pH = pKa + log [conjugate base] / [acid] 3 (C) Solution : pH = pKa + log [conjugate base] / [acid] So, pH = 10.00 + log (1.3 / 1.2) 10.00 + 0.03 = 10.03 Hence, pH of the buffer is 10.03. 4 (D) Answer : pH of buffer = 10.03
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