Chemistry: The Molecular Nature of Matter and Change 7th Edition

Published by McGraw-Hill Education
ISBN 10: 007351117X
ISBN 13: 978-0-07351-117-7

Chapter 19 - Problems - Page 869: 19.38

Answer

See explanation below.

Work Step by Step

1 Formula : 1. The Henderson - Hasselbalch equation of a buffer is as follows : pH = pKa + log [conjugate base] / [acid] 2. pKa = -log(Ka) 2 Solution : Here, 1. pH = 7.40 ........ (given) 2. Ka = 6.3 x 10^-8 ..... (from Appendix C) So, pKa = -log(Ka) = -log(6.3 x 10^-8) = 7.20 3. pH = pKa + log ([KH2PO4] / [Na2HPO4]) 7.40 = 7.20 + log (([KH2PO4] / [Na2HPO4])) log (([KH2PO4] / [Na2HPO4])) = 0.20 [KH2PO4] / [Na2HPO4] = Antilog (0.20) = 1.584 Hence, the buffer component ratio is equal to 1.584
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