Answer
Dissociation of $K_2CO_3$ in water:
$K_2CO_3(s) -^{H_2O}- \gt 2K^{+}(aq) + {CO_3}^{2-}(aq)$
Work Step by Step
- When strong electrolytes are added to water they dissociate, which means that they will divide, producing their ions.
1. Identify the cation and the anion in $K_2CO_3$
- Cations : 2 $K^{+}$
- Anion: 1 $C{O_3}^{2-}$
2. Write the equation for the dissociation:
$K_2CO_3(s) -^{H_2O}- \gt 2K^{+}(aq) + {CO_3}^{2-}(aq)$
** Remember: the ions are dissociated in an aqueous solution, so, their state symbol is "(aq)".