Answer
Dissociation of $K_3PO_4$ in water:
$K_3PO_4(s) -^{H_2O}- \gt 3K^{+}(aq) + P{O_4}^{3-}(aq)$
Work Step by Step
- When strong electrolytes are added to water they dissociate, which means that they will divide, producing their ions.
1. Identify the cation and the anion in $K_3PO_4$
- Cation : 3 $K^{+}$
- Anions: 1 $P{O_4}^{3-}$
2. Write the equation for the dissociation:
$K_3PO_4(s) -^{H_2O}- \gt 3K^{+}(aq) + P{O_4}^{3-}(aq)$
** Remember: the ions are dissociated in an aqueous solution, so, their state symbol is "(aq)".