Answer
An aqueous solution of $NaBr$ contains only ions.
Work Step by Step
Since $NaBr$ is a strong electrolyte, it will completely dissociate into $Na^+$ and $Br^-$ ions. That reaction can be represented by this equation:
$NaBr(s) -^{H_2O}-\gt Na^+(aq) + Br^-(aq)$.
Since the $NaBr$ is completely consumed, there are no molecules remaining in the solution. Only the produced ions ($Na^+$ and $Br^-$) will remain.
