Answer
Dissociation of $CuCl_2$ in water:
$CuCl_2(s) -^{H_2O}- \gt Cu^{2+}(aq) + 2Cl^{-}(aq)$
Work Step by Step
- When strong electrolytes are added to water they dissociate, which means that they will divide, producing their ions.
1. Identify the cation and the anion in $CuCl_2$
- Cation : 1 $Cu^{2+}$
- Anions: 2 $Cl^{-}$
2. Write the equation for the dissociation:
$CuCl_2(s) -^{H_2O}- \gt Cu^{2+}(aq) + 2Cl^{-}(aq)$
** Remember: the ions are dissociated in an aqueous solution, so, their state symbol is "(aq)".