Answer
250 J, 60 cal lost
Work Step by Step
$\Delta T = 118^{o}C - 224^{o}C = -106^{o}C$
Heat = mass x $\Delta T$ x SH
Heat (J)= 18g x $-106^{o}C$ x 0.129 J / g $^{o}C$
= -246.1 J
Heat (cal)= 18g x $-106^{o}C$ x .0308 cal / g $^{o}C$
= -58.8 cal