Answer
380 J, 90 cal
Work Step by Step
$\Delta T = 275^{o}C - 112^{o}C = 163^{o}C$
Heat = mass x $\Delta T$ x SH
Heat (J)= 10g x $163^{o}C$ x 0.235 J / g $^{o}C$
= 383 J
Heat (cal)= 10g x $163^{o}C$ x .0562 cal / g $^{o}C$
= 91.6 cal