Answer
1360 J, 330 cal
Work Step by Step
$\Delta T = 12.5^{o}C - 25.7^{o}C = -13^{o}C$
Heat = mass x $\Delta T$ x SH
Heat (J)= 25g x $-13^{o}C$ x 4.184 J / g $^{o}C$
= 1360 J
Heat (cal)= 25g x $-13^{o}C$ x 1 cal / g $^{o}C$
= 325 cal