Answer
$\dfrac{3}{4}$
Work Step by Step
$\sin{A} \cos{B} =\dfrac{1}{2}[\sin{(A+B)} + \sin{(A-B)}]$
$\sin{60} \cos{30} = \dfrac{1}{2}[\sin{90} + \sin{30}] = \dfrac{3}{4}$
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