Answer
$\dfrac{x}{\sqrt{1-x^2}}$
Work Step by Step
$\theta =\sin^{-1} {x}$
$\sin{\theta} =x$
$\cos{\theta} =\sqrt{1-\sin^2{\theta}} = \sqrt{1-x^2}$
$\tan{\theta} =\dfrac{\sin{\theta}}{\cos{\theta}} = \dfrac{x}{\sqrt{1-x^2}}$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 5 - Section 5.5 - Additional Identities - 5.5 Problem Set - Page 311: 15
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