Answer
$2x\sqrt{1-x^2}$
Work Step by Step
$\theta = \sin^{-1}{x}$
$\sin{\theta} =x$
$\cos{\theta} =\sqrt{1-\cos^2{\theta}} = \sqrt{1-x^2}$
$\sin{2\theta} = 2\sin{\theta} \cos{\theta} =2x\sqrt{1-x^2}$
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