Answer
$\dfrac{\sqrt{1-x^2}}{x}$
Work Step by Step
$\theta = \cos^{-1} {x} $
$\cos{\theta} =x$
$\sin{\theta} =\sqrt{1-\cos^2{\theta}} = \sqrt{1-x^2}$
$\tan{\theta} = \dfrac{\sin{\theta}}{\cos{\theta}} = \dfrac{\sqrt{1-x^2}}{x}$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 5 - Section 5.5 - Additional Identities - 5.5 Problem Set - Page 311: 16
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