Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 4 - Section 4.3 - Vertical and Horizontal Translations - 4.3 Problem Set - Page 217: 38

Answer

$Period = \frac{2\pi}{4} = \frac{\pi}{2}$ $Horizontal\ shift = –\frac{\pi}{4} = –\frac{\pi}{4}$ (Negative meaning left shift) $Phase = \pi$

Work Step by Step

If C is any real number and $B> 0$, then the graphs of $y = \sin(Bx+C)$ and $y = \cos (Bx+C)$ will have $Period = \frac{2\pi}{B}$ $Horizontal\ shift = –\frac{C}{B}$ $Phase = C$ so for $y = \sin (4x + \pi)$ $Period = \frac{2\pi}{4} = \frac{\pi}{2}$ $Horizontal\ shift = –\frac{\pi}{4} = –\frac{\pi}{4}$ Negative meaning left shift $Phase = \pi$
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