Answer
$Amplitude = \frac{1}{2}$
$Period = \frac{2\pi}{3}$
$Vertical\ translation = 1\ units\ upward$
See below
Work Step by Step
We know that
If C is any real number and $B> 0$, then the graphs of $y = k + A\sin(Bx+C)$ and $y = k + A\cos (Bx+C)$ will have
$Amplitude = |A|$
$Period = \frac{2\pi}{B}$
$ Vertical\ translation = k$
so for $y = 1 + \frac{1}{2} \sin 3x$
$Amplitude = |\frac{1}{2}| = \frac{1}{2}$
$Period = \frac{2\pi}{3}$
$ Vertical\ translation = 1 = 1\ units\ upward$
