Answer
$Amplitude = |1| = 1$
$Period = \frac{2\pi}{2} = \pi$
$Horizontal\ shift = –\frac{–\pi}{2} = \frac{\pi}{2}$
$Phase = –\pi$
Work Step by Step
If C is any real number and $B> 0$, then the graphs of $y = A\sin(Bx+C)$ and $y = A\cos (Bx+C)$ will have
$Amplitude = |A|$
$Period = \frac{2\pi}{B}$
$Horizontal\ shift = –\frac{C}{B}$
$Phase = C$
so for $y =\sin (2x – \pi)$
$Amplitude = |1| = 1$
$Period = \frac{2\pi}{2} = \pi$
$Horizontal\ shift = –\frac{–\pi}{2} = \frac{\pi}{2}$
$Phase = –\pi$
