Answer
$(4, 3)$
Work Step by Step
Given system is-
$x +y$ = $7$ __ eq.1
$2x -3y$ = $-1$ __ eq.2
Multiplying eq.1 by '3'-
$3x +3y$ = $21$ __ eq.3
Adding eq.2 and eq.3 -
$2x -3y+3x +3y$ = $-1+21$
i.e. $5x$ = $20$
i.e. $x$ = $\frac{20}{5}$
i.e. $x$ = $4$
Substituting for $x$ in eq.1
$4 +y$ = $7$
i.e. $y$ = $7-4$
i.e. $y$ = $3$
Thus $(4, 3)$ is the solution of given system.