Answer
$(-2, -12)$
Work Step by Step
Given system is-
$4x -3y$ = $28$ __ eq.1
$9x -y$ = $-6$ __ eq.2
Multiplying eq.2 by '3'-
$27x -3y$ = $-18$ __ eq.3
Subtracting eq.1 from eq.3 -
$(27x -3y)-(4x -3y)$ = $-18-28$
$27x -3y-4x +3y$ = $-46$
$23x $ = $-46$
i.e. $x$ = $\frac{-46}{23}$
i.e. $x$ = $-2$
Substituting for $x$ in eq.1
$4(-2) -3y$ = $28$
$-8 -3y$ = $28$
i.e. $-3y$ = $28+8$
$-3y$ = $36$
i.e. $y$ = $\frac{36}{-3}$
i.e. $y$ = $-12$
Thus $(-2, -12)$ is the solution of given system.