Answer
$(4,-6)$
Work Step by Step
Given system is-
$3x +2y$ = $0$ __ eq.1
$-x -2y$ = $8$ __ eq.2
Adding eq.1 and eq.2 -
$3x +2y-x -2y)$ = $0+8$
i.e. $2x$ = $8$
i.e. $x$ = $\frac{8}{2}$
i.e. $x$ = $4$
Substituting for $x$ in eq.1
$3(4) +2y$ = $0$
i.e. $2y$ = $-12$
i.e. $y$ = $-6$
Thus $(4,-6)$ is the solution of given system.