Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Review - Exercises - Page 136: 154

Answer

Approximately $329.4ft$

Work Step by Step

Let the maximum range of projectile be $R$ Velocity be $v$ And the constant of proportionality $k$ With the given information, we can write the relation: $R=kv^2$ $v=60mi/h$ $R=242ft$ $k$ is unknown $242=k\times 60^2$ $k=\frac{242}{3600}=\frac{121}{1800}$ If $v=70mi/h$ $R=\frac{121}{1800}\times4900=\frac{5929}{18}\approx 329.4ft$
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