Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Review - Exercises - Page 136: 153

Answer

Approximately $11.02mi/h$

Work Step by Step

Let the terminal velocity be $V$ Parachutist's weight $w$ And the constant of proportionality $k$ According to the information given, we can write the following equation: $V=k\sqrt{w}$ $w=160lb$ $V=9mi/h$ $k$ is unknown $9=k\sqrt{160}$ $k=\frac{9}{4\sqrt{10}}$ If $w=240lb$ $V=\frac{9}{4\sqrt{10}}\times \sqrt{240}=\frac{9\times4\sqrt{15}}{4\sqrt{10}}=\frac{9\sqrt{15}}{\sqrt{10}} = \frac{9\sqrt{15}\times\sqrt{10}}{\sqrt{10}\times\sqrt{10}}=\frac{5\times9\sqrt{6}}{10}=4.5\sqrt{6}\approx11.02mi/h$
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