Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Review - Exercises - Page 136: 150

Answer

$$z=\frac{192}{y}$$

Work Step by Step

According to the information given, we can write the following relation: $z=\frac{k}{y}$ To find the equation, we have to find the constant of proportionality ($k$). If $z=12$ and $y=16$ $12=\frac{k}{16}$ $k=12\times 16$ $k=192$ $z=\frac{192}{y}$
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