Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Review - Exercises - Page 136: 152

Answer

$8$ $inches$

Work Step by Step

Let the frequency of a vibrating string be $F$ Constant tension be $k$ And the length be $l$ We can write the relation: $F=\frac{k}{l}$ If $l=12in$ $F=440$ times per second $k$ is unknown $440=\frac{k}{12}$ $k=440\times12$ $k=5280$ We get general form: $F=\frac{5280}{l}$ If $F=660$ $660=\frac{5280}{l}$ $l=\frac{5280}{660}$ $l=8in$
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