Answer
$q^4-8q^3+24q^2-32q+16$
Work Step by Step
Use the formula $(a-b)^2=a^2-2ab+b^2$ , we have:
$(q-2)^4=(q-2)^2(q-2)^2=(q^2-4q+4)^2=[(q^2-4q)+4]^2=(q^2-4q)^2+2(q^2-4q)(4)+16=q^4-8q^3+16q^2+8q^2-32q+16=q^4-8q^3+24q^2-32q+16$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter R - Review of Basic Concepts - R.3 Polynomials - R.3 Exercises - Page 33: 85
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