Answer
$16y^2-8y+1+8yz-2z+z^2$
Work Step by Step
Use the formula $(a+b)^2=a^2+2ab+b^2$ and treat $4y-1$ as a single term, we have:
$[(4y-1)+z]^2=(4y-1)^2+2(4y-1)z+z^2=16y^2-8y+1+8yz-2z+z^2$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter R - Review of Basic Concepts - R.3 Polynomials - R.3 Exercises - Page 33: 78
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