Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.3 Polynomials - R.3 Exercises - Page 33: 81

Answer

$9a^2+6ab+b^2-6a-2b+1$

Work Step by Step

Use the formula $(a-b)^2=a^2-2ab+b^2$ and treat $3a+b$ as a single term, we have: $[(3a+b)-1]^2=(3a+b)^2-2(3a+b)+1=9a^2+6ab+b^2-6a-2b+1$
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