Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.3 Polynomials - R.3 Exercises - Page 33: 83

Answer

$y^3+6y^2+12y+8$

Work Step by Step

Use the formula $(a+b)^3=a^3+3a^2b+3ab^2+b^3$ , we have: $(y+2)^3=y^3+3y^2(2)+3y(2)^2+(2)^3=y^3+6y^2+12y+8$
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