Answer
$cscxsecx$
Work Step by Step
$\dfrac {secx}{cscx}+\dfrac {cscx}{secx}=\dfrac {\dfrac {1}{\cos x}}{\dfrac {1}{\sin x}}=\dfrac {\dfrac {1}{\sin x}}{\dfrac {1}{\cos x}}=\dfrac {\sin x}{\cos x}+\dfrac {\cos x}{\sin x}=\dfrac {\sin ^{2}x+\cos ^{2}x}{\sin x\cos x}=\dfrac {1}{\sin x\cos x}=cscxsecx$
