Answer
$sec\theta csc\theta $
Work Step by Step
$\cot \theta +\dfrac {1}{\cot \theta }=\dfrac {\cos a}{\sin \theta }+\dfrac {\sin a}{\cos \theta }=\dfrac {\sin ^{2}\theta +\cos ^{2}\theta }{\sin \theta \cos \theta }=\dfrac {1}{\sin \theta \cos \theta }=sec\theta csc\theta $
