Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - 7.2 Verifying Trigonometric Identities - 7.2 Exercises - Page 666: 17

Answer

$1-2\sin \alpha \cos \alpha =1-\sin 2\alpha $

Work Step by Step

$\left( \sin \alpha -\cos \alpha \right) ^{2}=\sin ^{2}\alpha -2\sin \alpha \cos \alpha +\cos ^{2}\alpha =1-2\sin \alpha \cos \alpha =1-\sin 2\alpha $
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