Answer
$1$
Work Step by Step
$\dfrac {1}{csc^{2}\theta }+\dfrac {1}{sec^2\theta }=\dfrac {1}{\dfrac {1}{\sin ^{2}\theta }}+\dfrac {1}{\dfrac {1}{\cos ^{2}\theta }}=\sin ^{2}\theta +\cos ^{2}\theta =1$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 7 - Trigonometric Identities and Equations - 7.2 Verifying Trigonometric Identities - 7.2 Exercises - Page 666: 15
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