Answer
See graph.
Work Step by Step
Given $f(x)=\frac{18+6x-4x^2}{4+6x+2x^2}=-\frac{2x^2-3x-9}{x^2+3x+2}=-\frac{(2x+3)(x-3)}{(x+1)(x+2)} $, we can identify: V.A. $x=-1,-2$, H.A. $y=-2$. See graph.
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