Answer
See graph.
Work Step by Step
Given $f(x)=\frac{x^4-20x^2+64}{x^4-10x^2+9}=\frac{(x^2-4)(x^2-16)}{(x^2-1)(x^2-9)}=\frac{(x-2)(x+2)(x-4)(x+4)}{(x-1)(x+1)(x-3)(x+3)}$, we can identify: V.A. $x=\pm1,\pm3$, H.A. $y=1$, O.A. $none$. See graph.