Answer
See graph.
Work Step by Step
Given $f(x)=\frac{4x^2+4x-24}{x^2-3x-10}=\frac{4(x+3)(x-2)}{(x+2)(x-5)}$, we can identify: V.A. $x=-2,5$, H.A. $y=4$. See graph.
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