Answer
See graph.
Work Step by Step
Given $f(x)=\frac{20+6x-2x^2}{8+6x-2x^2}=\frac{x^2-3x-10}{x^2-3x-4}=\frac{(x+2)(x-5)}{(x+1)(x-4)} $, we can identify: V.A. $x=-1,4$, H.A. $y=1$. See graph.
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