Answer
undefined.
Work Step by Step
Given $f(x)=\sqrt {x-2}$ and $g(x)=x^2$, we have
$(g\circ f)(-1)=g(f(-1))=g(\sqrt {-1-2})=g(\sqrt {-3})$ undefined.
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 2 - Graphs and Functions - Chapter 2 Test Prep - Review Exercises - Page 300: 117
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