Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - Chapter 2 Test Prep - Review Exercises - Page 300: 130

Answer

(a) $\frac{\pi}{4}d^3$ (b) $\frac{3\pi}{2}d^2$

Work Step by Step

(a) Let $h=d$ where $h$ is the height, we have $V=\pi (\frac{d}{2})^2h=\pi (\frac{d}{2})^2d=\pi (\frac{d^3}{4})=\frac{\pi}{4}d^3$ (b) We have $S=2\pi (\frac{d}{2})^2+\pi dh=\frac{\pi}{2}d^2+\pi d^2=\frac{3\pi}{2}d^2$
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