Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - Chapter 2 Test Prep - Review Exercises - Page 300: 115

Answer

$1$

Work Step by Step

Given $f(x)=\sqrt {x-2}$ and $g(x)=x^2$, we have $(g\circ f)(3)=g(f(3))=g(\sqrt {3-2})=g(1)=1^2=1$
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