Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - Chapter 2 Test Prep - Review Exercises - Page 300: 114

Answer

$\sqrt {x^2-2}$

Work Step by Step

Given $f(x)=\sqrt {x-2}$ and $g(x)=x^2$, we have $(f\circ g)(x)=f(g(x))=\sqrt {x^2-2}$
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