Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.3 Complex Numbers - 1.3 Exercises: 86

Answer

$E=260+20i$

Work Step by Step

$I=20+12i$ $;$ $Z=10-5i$ Ohm's Law is defined by the equation $E=IZ$. In this case, $E$ is unknown. Substitute $I$ and $Z$ into Ohm's Law equation: $E=(20+12i)(10-5i)=...$ Evaluate the product indicated to find $E$. Do so by multiplying each term of the first factor by every term of the second factor: $...=200-100i+120i-60i^{2}=...$ Substitute $i^{2}$ by $-1$ and simplify: $...=200+20i-60(-1)=200+20i+60=260+20i$
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