Answer
$(2+i)(3-2i)=8-i$
Work Step by Step
$(2+i)(3-2i)$
Evaluate the product by multiplying each term of the first factor by every term of the second factor:
$(2+i)(3-2i)=6-4i+3i-2i^{2}=...$
Substitute $i^{2}$ by $-1$ and simplify:
$...=6-4i+3i-2(-1)=6-i+2=8-i$
