Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.3 Complex Numbers - 1.3 Exercises: 82

Answer

$12i$

Work Step by Step

$\frac{12}{i} = \frac{12}{i} \times \frac{i}{i} = \frac{12i}{-i^2} = \frac{12i}{-(-1)} = \frac{12i}{1} = 12i$
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